So here's the problem, A+B=C and B>C, then absolutely B>A or B<A reasons:
Case 1: Since A+B=C. A, B cannot exceed C if they both are positive.
so 2 cases left are, (both negative) or (one negative and one positive).
Case 2: For both negative ( A and B ):
C will always be lesser than A and B
examples: -1-2=-3 (A=-1,B=-2,C=-3) or -2-1=-3 (A=-2,B=-1,C=-3), so B can be greater or less than A(In both examples B>C)
Case 3 (for one positive and one negative number): take examples, -1+2=1(A=-1,B=2,C=1) or 3-2=1(A=3,B=-2,C=1), in first case B>A (And B>C) and in second case B<A(B is not greater than C), so Answer is: 1) B is greater or less than A(If both numbers are negative)
2) B is greater than A (if A is negative and B is positive)
3) No relation (If both are positive numbers, or A is negative and B is positive)
P.S: A cannot be equal to B in any case(since B>C).
So according to the Question conditions of number being negative or positive, above three results can be obtained.)