Monster 'Mode' data

[Echoes]

Hello rAthena c:

 

I'm having some problems figuring out how to create the 'mode' for my custom mob since I don't know what do I need to do to obtain the desired one.

 

I'm using the mode numbers listed here: https://rathena.org/wiki/Custom_Mobs, but I don't want my mob to be just one mode.

 

Do I need to sum up the mode numbers there to obtain the desired AI?

 

Thank you

Edited September 17, 2016 by Echoes

[Playtester]

Why would you get that result?

 

Go digit by digit:

First digit: 2 (0x200000) = 2

Second digit: 8 (0x080000) = 8

Third digit: 1 (0x001000) + 2 (0x002000) + 4 (0x004000) = 7

Fourth digit: 2 (0x000200) = 2

Fifth digit: 1 (0x000010) + 2 (0x000020) + 8 (0x000080) = 11 = B

Sixth digit: 1 (0x000001) = 1

[nitrous]

Yup

Make sure you only add together the basic modes, not the combinations, as that will screw up the mode.

Edited August 30, 2016 by Nitrous

[FXFreitas]

This mode sytem is hexadecimal, when you add more than 1 modes you just need to combine them (just like equipables jobs for items).

But a common tip used is just use the mode from anoter mob, if you want a passive and looter monster, just use Poring's mode... or if want a agressive, cast detector, boss, just take Dark Priest's mode.

Edited August 30, 2016 by FXFreitas

[Secrets]

Mob modes in the wiki is outdated. Please refer to doc directory in your emulator directory instead.

[Playtester]

Link: https://github.com/rathena/rathena/blob/master/doc/mob_db_mode_list.txt

[Echoes]

Thank you for the information, and sorry for the late response.

MD_CANMOVE            | 0x000001 |        1
MD_LOOTER             | 0x000002 |        2
MD_AGGRESSIVE         | 0x000004 |        4
MD_ASSIST             | 0x000008 |        8
MD_CASTSENSOR_IDLE    | 0x000010 |       16
MD_BOSS               | 0x000020 |       32
MD_PLANT              | 0x000040 |       64
MD_CANATTACK          | 0x000080 |      128
MD_DETECTOR           | 0x000100 |      256
MD_CASTSENSOR_CHASE   | 0x000200 |      512
MD_CHANGECHASE        | 0x000400 |     1024
MD_ANGRY              | 0x000800 |     2048
MD_CHANGETARGET_MELEE | 0x001000 |     4096
MD_CHANGETARGET_CHASE | 0x002000 |     8192
MD_TARGETWEAK         | 0x004000 |    16384
MD_RANDOMTARGET       | 0x008000 |    32768
MD_IGNOREMELEE        | 0x010000 |    65536
MD_IGNOREMAGIC        | 0x020000 |   131072
MD_IGNORERANGED       | 0x040000 |   262144
MD_MVP                | 0x080000 |   524288
MD_IGNOREMISC         | 0x100000 |  1048576
MD_KNOCKBACK_IMMUNE   | 0x200000 |  2097152
MD_NORANDOM_WALK      | 0x400000 |  4194304
MD_NOCAST_SKILL       | 0x800000 |  8388608

According to what did you guys say, if I want monster with the next features:

MD_CANMOVE
MD_CASTSENSOR_IDLE
MD_BOSS
MD_CANATTACK
MD_CASTSENSOR_CHASE
MD_CHANGECHASE
MD_CHANGETARGET_MELEE
MD_CHANGETARGET_CHASE
MD_TARGETWEAK
MD_MVP
MD_KNOCKBACK_IMMUNE

I just need to sum up the values of those caracteristics, meaning:

0x(000001+000010+000020+000080+000200+001000+002000+004000+080000+200000) = 0x287311

 

And that last number is what I need to write in the mode section of the custom mob script?

 

Again, sorry for the late response, my week have been busy :c and thanks for the answers!

[Secrets]

I just need to sum up the values of those caracteristics, meaning:

0x(000001+000010+000020+000080+000200+001000+002000+004000+080000+200000) = 0x287311

 

And that last number is what I need to write in the mode section of the custom mob script?

Numbers prefixed with `0x` are in hexadecimal format (base 16, with range of 0 to F), so you can't add these up like they are base 10 numbers.

You might want to add base 10 numbers (1 2 4 8 ...) we noted together without adding 0x prefix instead.

[Echoes]

You might want to add base 10 numbers (1 2 4 8 ...) we noted together without adding 0x prefix instead.

So if I want the mob with the said features, the way to calculate the mode would be the next?

1+16+32+128+512+1024+4096+8192+16384+524288+2097152=2651825

[Playtester]

It's much easier, you just need to know:

 

A = 10

B = 11

C = 12

D = 13

E = 14

F = 15

 

0x(000001+000010+000020+000080+000200+001000+002000+004000+080000+200000) = 0x2872B1

 

You simply calculate per digit, no carrying over needed. That's the great thing about hex.

[Echoes]

It's much easier, you just need to know:

 

A = 10

B = 11

C = 12

D = 13

E = 14

F = 15

 

0x(000001+000010+000020+000080+000200+001000+002000+004000+080000+200000) = 0x2872B1

 

You simply calculate per digit, no carrying over needed. That's the great thing about hex.

But as you said, then I would think of the number 0x287311 to be 0x2873B, or is there another way to do the maths before and after adding the letter ?

[Playtester]

For some reason this reply displayed for me today. Maybe some bug with the year?

Anyway, if you still want the answer - I honestly don't understand how you can even reach that conclusion. When adding hexadecimals there's no number over flow. You just add per digit.

Take a look at the second digit from the right, you will have:

0 + 1 + 2 + 8 + 0 + 0 + 0 + 0 + 0 +0 = 11

11 in hexidecimal is a B. So the result for the second digit from the right is B. You do the same for every digit.