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Posted

Hello rAthena,

I've been using Euphy's Hunting Missions script and my server is just Mid Rate and the exp given is too high how can I reduce it.. 4m exp makes my base lvl 80+ and my job level 50+. So how can i reduce it to maybe like 600-700k exp per hunting mission.

SlashGeeGee

15 answers to this question

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Posted

it seems euphy still need more experience when trying to code out a user-friendly configuration lol

I added a comment explaining that. o.o

// Multipliers for Base Exp, Job Exp, and Zeny rewards.

Posted

You need to set the /100 to a larger number, not smaller.

if your rates are 200x, then this is what you will see: getbattleflag (2000) / 100 = 200. So making it smaller will increase the exp, and larger will decrease.

Posted (edited)

actually that time I also wanted to say it ... but dunno why I didn't, maybe too much topic to solve

in my version that I wrote,

http://rathena.org/board/topic/73115-hunting-mission-script-error/#entry150344

I used

set .baseexprate, getbattleflag("base_exp_rate");

this is very understandable .. means the rate is directly from your exp.conf

set .baseexprate, 1000; will overwrite the rate from exp.conf into 10x rate ... no mathematics calculation needed

but the way Euphy's did configuration makes the user need to do some math to figure out how to configure the rate lol

actually, his way

setarray .Modifier[0], 3,3,60;

if you do it this way means x3 baseexp, x3 jobexp, and 60x zeny modifier

still I need to read the script only understand about this ...

it seems euphy still need more experience when trying to code out a user-friendly configuration lol

EDIT: yeah, change that ... I'm sure in the future member who with low IQ will ask this question again

Edited by AnnieRuru
Posted

	// Reward formulas:

set .@Mission_Points, 3+(.@j[.Quests]/.Quests/6);

set .@Base_Exp, #Mission_Count*.@j[.Quests+1]/5;

set .@Job_Exp, #Mission_Count*.@j[.Quests+2]/5;

set .@Zeny, #Mission_Count*.Quests*.@j[.@i]*.Modifier[2];

Either increase the constant or decrease the divisor in the first formula.

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