Deleting char_id on an array

[pajodex]

Hi,

So I tested out a lot of things but this part seemed to be not working.

for(.@i=0; .@i < .@size; .@i++) {
        if (.char_id[.@i] == getcharid(0))
            cleararray .char_id[.@i],0,getcharid(0);
}

This supposed to delete char_id to the array.

Is there an alternative where I can retrieve the char_id list so I can remove the specific char_id listed? To explain futher:

array .char_id:
.char_id[0] = 150001
.char_id[1] = 150002
.char_id[2] = 150003
.char_id[3] = 150004

I want to remove .char_id[2] from the list. using:

deletearray .char_id[2],1;

so results will be:

.char_id[0] = 150001
.char_id[1] = 150002
.char_id[2] = 150004

I also tried this:

for(.@i=0; .@i < .@size; .@i++) {
        if (.char_id[.@i] == getcharid(0))
            deletearray .char_id[.@i],1;
}

but I figured that .@i is not = 2... I know you get what I mean xD 

 

Thanks for anybody interested in helping.

[Ajjwidjdneidjenw]

Is .@size defined? 
try
 

for(.@i=0; .@i < getarraysize(.char_id); .@i++) {
        if (.char_id[.@i] == getcharid(0))
            deletearray .char_id[.@i],1;
}

 

[pajodex]

1 minute ago, Jeroen said:

Is .@size defined? 
try
 

for(.@i=0; .@i < getarraysize(.char_id); .@i++) {
        if (.char_id[.@i] == getcharid(0))
            deletearray .char_id[.@i],1;
}

 

Will this part of the code ".@i"

deletearray .char_id[.@i],1;

locate the char_id of the invoking character?

Edited March 8, 2018 by pajodex

[Emistry]

.@aid = getcharid(0);
for(.@i = getarraysize(.char_id) - 1; .@i >= 0; .@i--) {
	if (.char_id[.@i] == .@aid)
		deletearray .char_id[.@i],1;
}

you could do it this way as well, loop from the end to the start...

this way you wont need to worry to recalculate the index in case you're intend to continue removing all the duplicates data in the array.