Lelouch vi Britannia Posted June 12, 2018 Group: Members Topic Count: 45 Topics Per Day: 0.01 Content Count: 715 Reputation: 84 Joined: 01/05/12 Last Seen: April 10, 2023 Share Posted June 12, 2018 (edited) Well the issue was the Coins are unidentified when it goes into the storage. Here is the script <?php class Coins { public $server; public $coinsID; public function __construct(Flux_Athena $server, $coinsID) { $this->server = $server; $this->coinsID = $coinsID; } public function getCoins($accountID) { $sql = "SELECT amount FROM {$this->server->loginDatabase}.storage WHERE account_id = ? AND nameid = ? LIMIT 1"; $sth = $this->server->connection->getStatement($sql); $sth->execute(array($accountID, $this->coinsID)); $num = $sth->fetch(); if ($num) { return (int)$num->amount; } else { return 0; } } public function setCoins($accountID, $amount) { $num = $this->getCoins($accountID); if (!$num) { $sql = "INSERT INTO {$this->server->loginDatabase}.storage (account_id, nameid, amount) "; $sql .= "VALUES (?, ?, ?)"; $sth = $this->server->connection->getStatement($sql); return $sth->execute(array($accountID, $this->coinsID, $amount)); } else { $sql = "UPDATE {$this->server->loginDatabase}.storage SET amount = ? WHERE account_id = ? AND nameid = ?"; $sth = $this->server->connection->getStatement($sql); return $sth->execute(array($amount, $accountID, $this->coinsID)); } } } ?> Edited June 12, 2018 by Lelouch vi Britannia Link to comment Share on other sites More sharing options...
0 Aries Posted June 13, 2018 Group: Members Topic Count: 9 Topics Per Day: 0.00 Content Count: 70 Reputation: 18 Joined: 01/28/12 Last Seen: May 10, 2021 Share Posted June 13, 2018 $sql = "INSERT INTO {$this->server->loginDatabase}.storage (account_id, nameid, amount, identify) "; $sql .= "VALUES (?, ?, ?, 1)"; update the insert part it should flag that the item is identified Link to comment Share on other sites More sharing options...
0 Lelouch vi Britannia Posted June 13, 2018 Group: Members Topic Count: 45 Topics Per Day: 0.01 Content Count: 715 Reputation: 84 Joined: 01/05/12 Last Seen: April 10, 2023 Author Share Posted June 13, 2018 12 hours ago, Aries said: $sql = "INSERT INTO {$this->server->loginDatabase}.storage (account_id, nameid, amount, identify) "; $sql .= "VALUES (?, ?, ?, 1)"; update the insert part it should flag that the item is identified Not Working Link to comment Share on other sites More sharing options...
0 Aries Posted June 13, 2018 Group: Members Topic Count: 9 Topics Per Day: 0.00 Content Count: 70 Reputation: 18 Joined: 01/28/12 Last Seen: May 10, 2021 Share Posted June 13, 2018 The amount will only get updated if you tested it on an account with coins already in storage. Try it again to an account without the coin in the storage. Link to comment Share on other sites More sharing options...
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Lelouch vi Britannia
Well the issue was the Coins are unidentified when it goes into the storage.
Here is the script
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